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Fix Array.sort_custom example code

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Array.sort_custom descending sort example was comparing index 0, but had expected result based on comparing index 1.  Updated to use index 1 consistently.
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aaronp64
2024-08-26 10:38:23 -04:00
parent e63c40e59c
commit 39ca8b4e23
1 changed files with 1 additions and 1 deletions
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doc/classes/Array.xml
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@ -728,7 +728,7 @@
print(my_items) # Prints [["Rice", 4], ["Tomato", 5], ["Apple", 9]] print(my_items) # Prints [["Rice", 4], ["Tomato", 5], ["Apple", 9]]
# Sort descending, using a lambda function. # Sort descending, using a lambda function.
my_items.sort_custom(func(a, b): return a[0] > b[0]) my_items.sort_custom(func(a, b): return a[1] > b[1])
print(my_items) # Prints [["Apple", 9], ["Tomato", 5], ["Rice", 4]] print(my_items) # Prints [["Apple", 9], ["Tomato", 5], ["Rice", 4]]
[/codeblock] [/codeblock]
It may also be necessary to use this method to sort strings by natural order, with [method String.naturalnocasecmp_to], as in the following example: It may also be necessary to use this method to sort strings by natural order, with [method String.naturalnocasecmp_to], as in the following example: