C#: Sync Plane with Core

- Add `Plane(Vector3)` constructor.
- Rename `IntersectRay` to `IntersectsRay`.
- Rename `IntersectSegment` to `IntersectsSegment`.
- Replace `Center` property with `GetCenter` method.
- Add and fix documentation about the _normal_ parameter
to Core and C# documentation.
This commit is contained in:
Raul Santos
2023-01-15 05:35:09 +01:00
parent cd3e03432a
commit 7a19c87c7e
2 changed files with 30 additions and 23 deletions

View File

@ -38,6 +38,7 @@
<param index="0" name="normal" type="Vector3" />
<description>
Creates a plane from the normal vector. The plane will intersect the origin.
The [param normal] of the plane must be a unit vector.
</description>
</constructor>
<constructor name="Plane">
@ -46,6 +47,7 @@
<param index="1" name="d" type="float" />
<description>
Creates a plane from the normal vector and the plane's distance from the origin.
The [param normal] of the plane must be a unit vector.
</description>
</constructor>
<constructor name="Plane">
@ -54,6 +56,7 @@
<param index="1" name="point" type="Vector3" />
<description>
Creates a plane from the normal vector and a point on the plane.
The [param normal] of the plane must be a unit vector.
</description>
</constructor>
<constructor name="Plane">
@ -152,7 +155,7 @@
In the scalar equation of the plane [code]ax + by + cz = d[/code], this is [code]d[/code], while the [code](a, b, c)[/code] coordinates are represented by the [member normal] property.
</member>
<member name="normal" type="Vector3" setter="" getter="" default="Vector3(0, 0, 0)">
The normal of the plane, which must be normalized.
The normal of the plane, which must be a unit vector.
In the scalar equation of the plane [code]ax + by + cz = d[/code], this is the vector [code](a, b, c)[/code], where [code]d[/code] is the [member d] property.
</member>
<member name="x" type="float" setter="" getter="" default="0.0">